Functor

The next algebraic structure we’ll look at is a functor. In the introduction, we saw that a category consists of objects and arrows. As an example, we morphed a set of strings to another set which contained the reverse of those strings. In other words, we morphed an object to another object. What if we could morph an entire category to another category while preserving the structure? Well, that’s what a functor does.

Formal Definition

Let and be categories. A functor is a map taking each -object to a -object and each -arrow to a arrow , such that all -objects and composable -arrows and

Example

Say we have a set . From this set we create another set which contains finite lists of elements drawn from . The functor we want maps from set to set. Since we know that a category contains objects and arrows, becomes the object part. The arrow part takes a function to a function that given a list maps over elements of

$$List(f)(L) = maplist(f)(L) = [f(s_1), f(s_2), f(s_3), ... f(s_n)]$$

How does this translate to code? This actually translates fairly easily to code. Containers like lists, trees, etc. that you can call map on are functors.

Let’s write some code. We’ll begin by creating a set .

@ val S = Set(0, 1, 2, 3, 4, 5, 6, 7, 8, 9)
S: Set[Int] = Set(0, 5, 1, 6, 9, 2, 7, 3, 8, 4)

Next, we’ll create .

@ def f(x: Int) = { x * 2 }
defined function f

Next, let’s create .

@ val L = List(1, 2, 3)
L: List[Int] = List(1, 2, 3)

Next, we’ll create the function maplist.

@ def maplist(f: Int => Int)(L: List[Int]) = L map f
defined function maplist

Finally, let’s see this in action:

@ maplist(f)(L)
res4: List[Int] = List(2, 4, 6)

As we can see, maplist applied the function f on all elements of L. We did this by using the map method of a List instance.

Functor Laws

All functors are expected to obey the two laws that we saw in the formal definition. Let’s see how they translate to code.

First Law

$$F(id_A) = id_{F(A)}$$

The first law states that if we map the identity function over a functor, we’ll get back a functor which is the same as the original functor.

@ List(1, 2, 3) map identity
res5: List[Int] = List(1, 2, 3)

As we can see, applying identity to the list gives back the same list.

Second Law

$$F(g \circ f) = F(g) \circ F(f)$$

The second law states that if we map a functor using a composition of two functions, , it’s the same as first mapping the functor using the first function and then mapping the resulting functor using the second function, .

We’ll begin by creating two functions f and g.

@ def f(x: Int): Int = x + 1
defined function f
@ def g(x: Int): Int = x + 1
defined function g

Now let’s put the theory into practice.

// composition of two functions
@ List(1, 2, 3) map { x => g(f(x)) }
res8: List[Int] = List(3, 4, 5)

// applying map twice
@ List(1, 2, 3) map f map g
res9: List[Int] = List(3, 4, 5)

As we see, the two lists are the same.

More Functor Examples

Example 1

Let’s consider a category where objects are integers. Arrows between objects indicates a “divided by” relationship. For example,

$$10 \rightarrow 5$$

This indicates that 10 can be divided by 5. To reiterate, objects are numbers and arrows represent a “divided by” relationship.

Now let’s create a functor from the category to itself. This functor will multiply each object by 13. So, . Is this a valid functor? We have but is it true that ?

The answer is yes. Our category has arrows that indicate a “divided by” relationship. So, will be an integer. Similarly, will also be an integer and maintain a “divided by” relationship. This shows that arrows do not always have to be functions. They can also indicate a relationship between their domain and codomain.

Conclusion

In this post we saw functors which map objects from one category to another. Containers like trees, lists, etc. are functors. All functors are required to obey the two functor laws.